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bacali: Master | Next Rank: 500 Posts; Posts: 245; Joined: Thu Aug 16, 2007 12:41 pm

by bacali » Sun Nov 30, 2008 8:18 am

Q27:

A store’s selling price of $2,240 for a certain computer would yield a profit of 40 percent of the store’s cost for the computer. What selling price would yield a profit of 50 percent of the computer’s cost?
A. $2,400
B. $2,464
C. $2,650
D. $2,732
E. $2,800

OA: A

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Source: Beat The GMAT — Problem Solving | Sun Nov 30, 2008 8:18 am

dmateer25: Community Manager; Posts: 1049; Joined: Sun Apr 06, 2008 5:15 pmFollowed by: 27 members; Location: Pittsburgh, PA; Thanked: 113 times; GMAT Score:710

by dmateer25 » Sun Nov 30, 2008 8:25 am

Let stores cost=x

1.4x=2240
x=1600

So the store paid 1600 for a computer.

1.5 times 1600 would yield a 50% profit for the store.

1600 x 1.5 =2400

A

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niraj_a: Legendary Member; Posts: 708; Joined: Sun Jun 01, 2008 4:59 amFollowed by: 1 member; Location: USA; Thanked: 13 times

by niraj_a » Sun Nov 30, 2008 8:27 am

lets say C = cost.

2240 - C = .40C
2240 = .40C + C
2240 = 1.40 C
2240 / 1.40 = C
224000/140 = C

1600 = C

now, lets say the new selling price needed is X.

X - 1600 = .50(1600)
X - 1600 = 800
X = 800 + 1600 = 2400

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PAB2706: Master | Next Rank: 500 Posts; Posts: 260; Joined: Sun Oct 12, 2008 8:10 pm; Thanked: 4 times

by PAB2706 » Sun Nov 30, 2008 8:52 am

we can do in this way also i guess....its a simple way

2240 => 140

? => 150

direct proportion..gives 150=>2400

So A

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