BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Pushing Probability to Punishing Exhaustion

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 487
Joined: Fri Mar 27, 2009 5:49 am
Thanked: 36 times
by dtweah » Wed May 13, 2009 5:02 pm
A and B play a series of games; the winner of each game has probability 0.8 of winning the next game. If A wins the first game, what is the probability A will win the third game?

(a) .68
(b) .76
(c) .72
(d) .60
(e) .64
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Junior | Next Rank: 30 Posts
Posts: 16
Joined: Mon Sep 01, 2008 8:13 pm
Thanked: 3 times
GMAT Score:700

by ontherocks27 » Wed May 13, 2009 11:29 pm
There are two ways in which A can win the 3rd game after winning the first game

1st way: A wins 2nd game and A wins 3rd game
Probablity = 0.8 * 0.8 = 0.64

or

2nd way: B wins 2nd game and A wins 3rd game
Probablity = (1-0.8) * (0.2) = 0.2*0.2 = 0.04

Overall probability of A winning the 3rd game = 0.64+0.04=0.68

Hence (A)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
GMAT Instructor
Posts: 3650
Joined: Wed Jan 21, 2009 4:27 amFollowed by: 80 members
Location: India
Thanked: 267 times
GMAT Score:760

by sanju09 » Thu May 14, 2009 4:54 am
After A wins the first game, A can win the third game in two situations

1. A loses second and wins the third: probability = 0.2 × 0.2 = 0.04. OR
2. A wins second and also the third: probability = 0.8 × 0.8 = 0.64.

Total probability = 0.04 + 0.64 + 0.68. My [spoiler]A[/spoiler].

Explanation: In case 1, A loses second means B wins, and A wins third means B loses. See how the probabilities change as per the condition given. Hope no doubts.
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1