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Purple balls

Expert replies
by Cheese12 » Sun Oct 02, 2011 6:57 am
In a certain game, a large bag is filled with blue, green, purple and red chips worth 1, 5, x and 11 points each, respectively. The purple chips are worth more than the green chips, but less than the red chips. A certain number of chips are then selected from the bag. If the product of the point values of the selected chips is 88,000, how many purple chips were selected?

A) 1
B) 2
C) 3
D) 4
E) 5

Im stuck with this problem and dont know how to proceed.. My working..

Total points = 88000
factor using primes -> 88000 = (2^6)*(5^3)*(11)

from question we know that ... 88000= B*5G*Px*R11

and 11>x>5... so x = 8 or 10...8= 2^3... and 10= 2*5... both can be a fit into the formula..
also.. what about the Blue balls(B) ?... they could be any number.. and still hold true if x was 8 or 10...

OA:B
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Source: — Problem Solving |

by knight247 » Sun Oct 02, 2011 7:34 am
Actually, u've answered ur own question. 10=2*5 so the 5 would be a part of the green chips picked up. Secondly, when u have 2^6 i.e. 64 left you need to find a number between 5 and 11 which when multiplied by itself a certain number of times would give u 64. Only the number 8 when multiplied twice i.e. 8^2 gives u 64. Hence, there are two chips of 8 that were picked up. Hence, B. Hope that clears ur doubts.
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by edvhou812 » Sun Oct 02, 2011 7:55 am
88,000=11^1*2^6*5^3
2^6=64=8*8
5<8<11
B
I don't know what to say, really. Three minutes to the biggest battle of our professional lives. You find out life's this game of inches, so is football. Because in either game - life or football - the margin for error is so small. I mean, one half a step too late or too early and you don't quite make it. One half second too slow, too fast and you don't quite catch it. I'll tell you this, in any fight it's the guy whose willing to die whose gonna win that inch. That's football guys, that's all it is. Now, what are you gonna do?
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by Cheese12 » Sun Oct 02, 2011 8:08 am
knight247 wrote:Actually, u've answered ur own question. 10=2*5 so the 5 would be a part of the green chips picked up. Secondly, when u have 2^6 i.e. 64 left you need to find a number between 5 and 11 which when multiplied by itself a certain number of times would give u 64. Only the number 8 when multiplied twice i.e. 8^2 gives u 64. Hence, there are two chips of 8 that were picked up. Hence, B. Hope that clears ur doubts.
Hi Knight247,

that means... B*5G*Px= 2^6 * 5^3
so this can mean that G=3,2,1 ... if G=1 and say x = 10=5*2.. that means we have two 10's (2 5's and 2 2's) ..

so then the formula becomes... B =2^4... which is possible right ?

please help to point out my mistake here... thanks!!!
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by knight247 » Sun Oct 02, 2011 8:24 am
It is not B*5G*Px. It should be 5^(the number of times G is picked up) as it is the product of all the Gs picked up and not the sum of them. Similarly for other chips.

88,000=11^1 * 2^6 * 5^3

So we have, 1 Red Chip, 3 Green chips and 2^6 which is not defined yet. We don't consider Blue chips because their value is one, so picking a blue chip multiple times would not affect the product of the points. So the mistake u've made is that u've considered 5G when it should be
5^(the number of times G is picked up). Remember it is the product of all points.Similarly for other chips.
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