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by [email protected] » Tue Oct 09, 2007 5:13 pm
For every positive even integer n, the function h(n) equals the product of all even integers from 2 to n, inclusive. If P is the smallest prime factor of h(100)+1, then P is...

1) Between 2 and 10
2) Between 10 and 20
3) Between 20 and 30
4) Between 30 and 40
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by kajcha » Tue Oct 09, 2007 7:38 pm
h(100) = 2* 4* 6* ..... *98*100

=> 2*(2*2)*(2*3)....*(2*49)*(2*50)

=> (2^50)(1*2*3....*49*50)

Means - all integers from 1 to 50 are factors of h(100). So, none of them will be factor of h(100)+1

So, smallest prime factor of h(100)+1 will be greater than 50

I think you are missing one option from ur answers choices....
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by [email protected] » Tue Oct 09, 2007 8:34 pm
you are correct
The last answer was > 40
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by kajcha » Tue Oct 09, 2007 8:54 pm
Yes and that would be the answer
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by samirpandeyit62 » Wed Oct 10, 2007 3:43 am
I agree with kajcha.
Regards
Samir
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