If each term in a1, a2, a3,.....,an is either 7 or 77 and the sum is 350 what is the value of n?
a)39
b)40
c)41
d)42
e)43
a)39
b)40
c)41
d)42
e)43
Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.
See classesLearn live with an expert or move at your own pace. Every option includes the complete TTP study system.
Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.
with Josh Braslow, 20+ years in test prep
Self-paced EA prep. Study on your schedule.
with
Complete access from day one. Study on your schedule.
Notice that 77 does not divide into 350 many times.kkadvent wrote:If each term in a1, a2, a3,.....,an is either 7 or 77 and the sum is 350 what is the value of n?
a)39
b)40
c)41
d)42
e)43
Another possible approach is to look for a pattern.kkadvent wrote:If each term in a1, a2, a3,.....,an is either 7 or 77 and the sum is 350 what is the value of n?
a)39
b)40
c)41
d)42
e)43
The important part of the problem is that sum is 350 which shows 0 as a unit digit.kkadvent wrote:If each term in a1, a2, a3,.....,an is either 7 or 77 and the sum is 350 what is the value of n?
a)39
b)40
c)41
d)42
e)43
Brent@GMATPrepNow wrote:Another possible approach is to look for a pattern.kkadvent wrote:If each term in a1, a2, a3,.....,an is either 7 or 77 and the sum is 350 what is the value of n?
a)39
b)40
c)41
d)42
e)43
Since both 7 and 77 have 7 as their units digit, we know that if we take any two terms, their sum will have a units digit of 4 (e.g., 7 + 7 = 14, 7 + 77 = 84, 77 + 77 = 154)
Similarly, if we take any three terms, their sum will have a units digit of 1. (e.g., 7 + 7 + 7 = 21, 7 + 7 + 77 = 91, etc.)
Now let's look for a pattern.
The sum of any 1 term will have units digit 7
The sum of any 2 terms will have units digit 4
The sum of any 3 terms will have units digit 1
The sum of any 4 terms will have units digit 8
The sum of any 5 terms will have units digit 5
The sum of any 6 terms will have units digit 2
The sum of any 7 terms will have units digit 9
The sum of any 8 terms will have units digit 6
The sum of any 9 terms will have units digit 3
The sum of any 10 terms will have units digit 0
The sum of any 11 terms will have units digit 7 (at this point, the pattern repeats)
From this, we can conclude that the sum of any 20 terms will have units digit 0
And the sum of any 30 terms will have units digit 0, and so on.
We are told the sum of the terms is 350 (units digit 0), so the number of terms must be 10 or 20 or 30 or . . .
Since B is a multiple of 10, this must be the correct answer.
Cheers,
Brent
Let x = the number of 7's and y = the number of 77's.kkadvent wrote:If each term in a1, a2, a3,.....,an is either 7 or 77 and the sum is 350 what is the value of n?
a)39
b)40
c)41
d)42
e)43