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PS question a Day

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by ajith » Mon Oct 30, 2006 3:22 am
PS001


The cost of picture frame M is $10.00 less than 3 times the cost of picture frame N. If the cost of frame M is $50.00, what is the cost of frame N?

A) $13.33
B) $16.66
C) $20.00
D) $26.66
E) $40.00


Answers in three days of time
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Source: — Problem Solving |

by limits660 » Mon Oct 30, 2006 5:12 am
I could of made a mistake but i believe the answer is A, $13.33

M = 3N - 10

M = 50

therefore

50 = 3N - 10
.
.
.
N = $13.33
-
Jeff Sacco
www.jeffsacco.ca
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by rajs.kumar » Mon Oct 30, 2006 9:30 am
limits660 wrote:I could of made a mistake but i believe the answer is A, $13.33

M = 3N - 10

M = 50

therefore

50 = 3N - 10
.
.
.
N = $13.33
Answer is 20. Limits if you substitute your answer you should satisfy the question. $10 less than 3 times $13.33 is approximately equal to 30 and not 50.
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by limits660 » Mon Oct 30, 2006 10:13 am
Ahhhhh, now i see it

thanks :)
-
Jeff Sacco
www.jeffsacco.ca
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PS002

by ajith » Mon Oct 30, 2006 10:46 pm
PS002

A piece of embroidered fabric is held in a circular wooden hoop. If the area of the fabric framed by the hoop is x square feet, and the hoop has a radius of x feet, then x equals

A) 2*pi
B) 2
C) pi/2
D) 1/2
E) 1/pi
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Re: PS002

by Monica » Tue Oct 31, 2006 8:25 am
ajith wrote:PS002

A piece of embroidered fabric is held in a circular wooden hoop. If the area of the fabric framed by the hoop is x square feet, and the hoop has a radius of x feet, then x equals

A) 2*pi
B) 2
C) pi/2
D) 1/2
E) 1/pi
Is the answer E?
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Re: PS002

by rajs.kumar » Tue Oct 31, 2006 8:41 am
ajith wrote:PS002

A piece of embroidered fabric is held in a circular wooden hoop. If the area of the fabric framed by the hoop is x square feet, and the hoop has a radius of x feet, then x equals

A) 2*pi
B) 2
C) pi/2
D) 1/2
E) 1/pi
area of the circle with radius x = pi * x^2 = x

=> x = 1/pi

Answer is E.
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Re: PS002

by ajith » Tue Oct 31, 2006 9:00 pm
Monica wrote:
ajith wrote:PS002

A piece of embroidered fabric is held in a circular wooden hoop. If the area of the fabric framed by the hoop is x square feet, and the hoop has a radius of x feet, then x equals

A) 2*pi
B) 2
C) pi/2
D) 1/2
E) 1/pi
Is the answer E?
Welcome to the forums Monica, answers will be posted in the same thread on the 3rd day. Keep checking the thread, and participate actively. Thanks
Always borrow money from a pessimist, he doesn't expect to be paid back.
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Re: PS question a Day

by ajith » Wed Nov 01, 2006 8:10 pm
ajith wrote:PS001


The cost of picture frame M is $10.00 less than 3 times the cost of picture frame N. If the cost of frame M is $50.00, what is the cost of frame N?

A) $13.33
B) $16.66
C) $20.00
D) $26.66
E) $40.00


Answers in three days of time
3days are over and now I have to answer...


3N-10=M=50
N=(50+10)/3=20
Answer is C.
Always borrow money from a pessimist, he doesn't expect to be paid back.
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PS003

by ajith » Wed Nov 01, 2006 8:26 pm
PS003

A certain company that sells only cars and trucks reported that revenues from car sales in 1997 were down 11 percent from 1996 and revenues from truck sales in 1997 were up 7 percent from 1996. If total revenues from car sales and truck sales in 1997 were up 1 percent from 1996, what is the ratio of revenue from car sales in 1996 to revenue from truck sales in 1996?
A. 1 : 2
B. 4 : 5
C. 1 : 1
D. 3 : 2
E. 5 : 3
Always borrow money from a pessimist, he doesn't expect to be paid back.
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Re: PS003

by rajs.kumar » Thu Nov 02, 2006 4:14 am
ajith wrote:PS003

A certain company that sells only cars and trucks reported that revenues from car sales in 1997 were down 11 percent from 1996 and revenues from truck sales in 1997 were up 7 percent from 1996. If total revenues from car sales and truck sales in 1997 were up 1 percent from 1996, what is the ratio of revenue from car sales in 1996 to revenue from truck sales in 1996?
A. 1 : 2
B. 4 : 5
C. 1 : 1
D. 3 : 2
E. 5 : 3
Rc and Rt are car and truck revenues in 96.
0.89Rc and 1.07Rt are care and truck revenues in 97.

0.89Rc + 1.07Rt = 1.01Rc + 1.01 Rt

0.06Rt = 0.12Rc => Rc/Rt = 1/2 (A)
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PS004

by ajith » Thu Nov 02, 2006 9:29 pm
PS004


3 boxes of supplies have an average (arithmetic mean) weight of 7 kilograms and a median weight of 9 kilograms. What is the maximum possible weight, in kilograms, of the lightest box?

1
2
3
4
5
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PS002 answers

by ajith » Thu Nov 02, 2006 9:32 pm
ajith wrote:PS002

A piece of embroidered fabric is held in a circular wooden hoop. If the area of the fabric framed by the hoop is x square feet, and the hoop has a radius of x feet, then x equals

A) 2*pi
B) 2
C) pi/2
D) 1/2
E) 1/pi
E it is

pi*x^2=x

x=1/pi
Always borrow money from a pessimist, he doesn't expect to be paid back.
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Re: PS004

by rajs.kumar » Fri Nov 03, 2006 1:38 am
ajith wrote:PS004


3 boxes of supplies have an average (arithmetic mean) weight of 7 kilograms and a median weight of 9 kilograms. What is the maximum possible weight, in kilograms, of the lightest box?

1
2
3
4
5
Answer is 3.

Total weight = 3 x 7 = 21

x+y+z = 21

y = 9

Maximise x => minimise z, which gives x = 3.
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On a break

by ajith » Tue Nov 07, 2006 11:23 pm
I am sorry, guys

I am on a break till 19th of this month ,

Be back after that.

If somebody can manage this this thread till then I will be grateful,

Miss u guys,

Ajith
Always borrow money from a pessimist, he doesn't expect to be paid back.
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