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PS - Prime factorisation

Expert replies
by karthikpandian19 » Fri Jun 22, 2012 4:21 pm
If x is a positive integer and x^2 is divisible by 32, then the largest positive integer that must divide x is


(A) 2

(B) 6

(C) 8

(D) 12

(E) 16
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The source of the questions that i post from JUNE 2013 is from KNEWTON

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Source: — Problem Solving |

by GMATGuruNY » Fri Jun 22, 2012 6:11 pm
karthikpandian19 wrote:If x is a positive integer and x^2 is divisible by 32, then the largest positive integer that must divide x is


(A) 2

(B) 6

(C) 8

(D) 12

(E) 16
When a problem asks what MUST be true, the goal is to show that the answers DON'T have to be true.
To prove that the greatest answer choice here -- 16 -- does NOT have to be a factor of x, we must MINIMIZE the value of x.

A perfect square such as x² must be composed of an even number of prime factors.
For x² to be a multiple of 32, its prime-factorization must include at a minimum 2*2*2*2*2.
Since x² must be composed of an even number of prime factors, the smallest possible value of x² = 2*2*2*2*2*2.
Thus, the smallest possible value of x = 2*2*2.
Thus, the greatest integer that must be a factor of x is 8.

The correct answer is C.
Last edited by GMATGuruNY on Sat Jun 23, 2012 3:34 am, edited 1 time in total.
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by Anurag@Gurome » Fri Jun 22, 2012 9:55 pm
karthikpandian19 wrote:If x is a positive integer and x^2 is divisible by 32, then the largest positive integer that must divide x is
To determine the largest positive integer that must divide x, we have to minimize x.

Now, smallest multiple of 32 which is square of an integer is 64. Hence, minimum possible value of x² is 64.

Therefore, minimum possible value of x is 8.
Hence, the largest positive integer that must divide x is 8.

The correct answer is C.
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by thakur2 » Sat Jun 23, 2012 1:40 am
I was a bit confused in the beginning about what the question really asked. The word to be noticed is 'must'. So if x=8, then 8 is the largest integer that must divide it and if x is any other value larger than 8, still 8 would remain the largest such integer because minimum value of x is the one to give the answer.

C
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by karthikpandian19 » Sat Jun 23, 2012 1:00 pm
OA is C
Regards,
Karthik
The source of the questions that i post from JUNE 2013 is from KNEWTON

---If you find my post useful, click "Thank" :) :)---
---Never stop until cracking GMAT---
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