Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 563 reviewsTarget Test Prep

PS Practice test question #4

Expert replies
Post new topic Post Reply
Subscribe topic
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 288
Joined: Thu Jul 31, 2008 10:54 pm
Location: Bombay, India
by missionmba » Sat Aug 16, 2008 1:18 am
A certain smelting plant operates 24 hours per day, with three shifts of 200 workers per shift. Due to a flu epidemic, of the workers on the first shift, 10 percent of the workers on the second shift, and 100 of the workers on the third shift are unable to work on a given day. If each worker and each shift has the same productivity, what is the approximate percent decrease in productivity due to the flu epidemic?


6%

12%

14%

24%

28%
Mission Mba

Everyone has a will to win but very few have the will to prepare to win
Top
Join the discussion
Source: — Problem Solving |
Legendary Member
Posts: 829
Joined: Mon Jul 07, 2008 10:09 pmFollowed by: 3 members
Location: INDIA
Thanked: 84 times

by sudhir3127 » Sat Aug 16, 2008 1:31 am
hey be careful while posting questions.. u missed the % of employees sick on first shift..?
Top
Join the discussion
Legendary Member
Posts: 661
Joined: Tue Jul 08, 2008 12:58 pm
Location: France
Thanked: 48 times

by pepeprepa » Sat Aug 16, 2008 1:51 am
With the current question, it gives around 20%...
Top
Join the discussion
Master | Next Rank: 500 Posts
Posts: 288
Joined: Thu Jul 31, 2008 10:54 pm
Location: Bombay, India

by missionmba » Sat Aug 16, 2008 8:39 pm
sudhir3127 wrote:hey be careful while posting questions.. u missed the % of employees sick on first shift..?
I have cross checked.

See the screen print of the que.
You do not have the required permissions to view the files attached to this post.
Mission Mba

Everyone has a will to win but very few have the will to prepare to win
Top
Join the discussion
Master | Next Rank: 500 Posts
Posts: 288
Joined: Thu Jul 31, 2008 10:54 pm
Location: Bombay, India

by missionmba » Sat Aug 16, 2008 8:41 pm
pepeprepa wrote:With the current question, it gives around 20%...
This que is from one of the princeton CAT's

and it says the ans should be E
Mission Mba

Everyone has a will to win but very few have the will to prepare to win
Top
Join the discussion
Legendary Member
Posts: 829
Joined: Mon Jul 07, 2008 10:09 pmFollowed by: 3 members
Location: INDIA
Thanked: 84 times

by sudhir3127 » Sat Aug 16, 2008 9:16 pm
missionmba wrote:
sudhir3127 wrote:hey be careful while posting questions.. u missed the % of employees sick on first shift..?
I have cross checked.

See the screen print of the que.
If u realise u never quoted 1/4 in ur original question..
Okai thats fine ..be careful the next time...

here goes the solution ..Its E.

total employess 3*200 = 600

total productivity = 600*24( 24 hrs in a day) = 14400

number of employees sick in first shift
1/4*200 = 50

second shift 10% = 0.1*200 = 20

third shift =100

thus .. total number of employess sick = 50+20+100 = 170

loss of productivity = (170*24)/14400 = 28.33 % henve E.

hope it helps..do let us know if u have any doubts..

PS: u can also consider dividing 170/600 = 28% as we know that the productivity is same for all employee.. i just used a more formal approach so that its easier for you to understand the concept.
Top
Join the discussion
Legendary Member
Posts: 661
Joined: Tue Jul 08, 2008 12:58 pm
Location: France
Thanked: 48 times

by pepeprepa » Sun Aug 17, 2008 1:13 am
Your screen print and what you posted in your original post have different figures which are relevant for the questions. Try to check your question.
Top
Join the discussion
Legendary Member
Posts: 891
Joined: Sat Aug 16, 2008 4:21 amFollowed by: 1 member
Thanked: 27 times
GMAT Score:660(

by 4meonly » Sun Aug 17, 2008 4:27 am
sudhir3127 wrote:
missionmba wrote:
sudhir3127 wrote:hey be careful while posting questions.. u missed the % of employees sick on first shift..?
I have cross checked.

See the screen print of the que.
If u realise u never quoted 1/4 in ur original question..
Okai thats fine ..be careful the next time...

here goes the solution ..Its E.

total employess 3*200 = 600

total productivity = 600*24( 24 hrs in a day) = 14400

number of employees sick in first shift
1/4*200 = 50

second shift 10% = 0.1*200 = 20

third shift =100

thus .. total number of employess sick = 50+20+100 = 170

loss of productivity = (170*24)/14400 = 28.33 % henve E.

hope it helps..do let us know if u have any doubts..

PS: u can also consider dividing 170/600 = 28% as we know that the productivity is same for all employee.. i just used a more formal approach so that its easier for you to understand the concept.
Yes, thanx!
We can solve it with out multiplying on 24, making the productivity of each employee equal to 1.

So, before the epidemic there were 200*3=600 employees.
After epidemic: (200-25%*200)+(200-10%*200)+(200-100)=430
(600-430)/600=170/600=0,28333 approx 28%
Top
Join the discussion