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PS Practice test question #4

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PS Practice test question #4

by missionmba » Sat Aug 16, 2008 1:18 am
A certain smelting plant operates 24 hours per day, with three shifts of 200 workers per shift. Due to a flu epidemic, of the workers on the first shift, 10 percent of the workers on the second shift, and 100 of the workers on the third shift are unable to work on a given day. If each worker and each shift has the same productivity, what is the approximate percent decrease in productivity due to the flu epidemic?


6%

12%

14%

24%

28%
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by sudhir3127 » Sat Aug 16, 2008 1:31 am
hey be careful while posting questions.. u missed the % of employees sick on first shift..?
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by pepeprepa » Sat Aug 16, 2008 1:51 am
With the current question, it gives around 20%...
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by missionmba » Sat Aug 16, 2008 8:39 pm
sudhir3127 wrote:hey be careful while posting questions.. u missed the % of employees sick on first shift..?
I have cross checked.

See the screen print of the que.
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PS.JPG
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by missionmba » Sat Aug 16, 2008 8:41 pm
pepeprepa wrote:With the current question, it gives around 20%...
This que is from one of the princeton CAT's

and it says the ans should be E
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by sudhir3127 » Sat Aug 16, 2008 9:16 pm
missionmba wrote:
sudhir3127 wrote:hey be careful while posting questions.. u missed the % of employees sick on first shift..?
I have cross checked.

See the screen print of the que.
If u realise u never quoted 1/4 in ur original question..
Okai thats fine ..be careful the next time...

here goes the solution ..Its E.

total employess 3*200 = 600

total productivity = 600*24( 24 hrs in a day) = 14400

number of employees sick in first shift
1/4*200 = 50

second shift 10% = 0.1*200 = 20

third shift =100

thus .. total number of employess sick = 50+20+100 = 170

loss of productivity = (170*24)/14400 = 28.33 % henve E.

hope it helps..do let us know if u have any doubts..

PS: u can also consider dividing 170/600 = 28% as we know that the productivity is same for all employee.. i just used a more formal approach so that its easier for you to understand the concept.
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by pepeprepa » Sun Aug 17, 2008 1:13 am
Your screen print and what you posted in your original post have different figures which are relevant for the questions. Try to check your question.
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by 4meonly » Sun Aug 17, 2008 4:27 am
sudhir3127 wrote:
missionmba wrote:
sudhir3127 wrote:hey be careful while posting questions.. u missed the % of employees sick on first shift..?
I have cross checked.

See the screen print of the que.
If u realise u never quoted 1/4 in ur original question..
Okai thats fine ..be careful the next time...

here goes the solution ..Its E.

total employess 3*200 = 600

total productivity = 600*24( 24 hrs in a day) = 14400

number of employees sick in first shift
1/4*200 = 50

second shift 10% = 0.1*200 = 20

third shift =100

thus .. total number of employess sick = 50+20+100 = 170

loss of productivity = (170*24)/14400 = 28.33 % henve E.

hope it helps..do let us know if u have any doubts..

PS: u can also consider dividing 170/600 = 28% as we know that the productivity is same for all employee.. i just used a more formal approach so that its easier for you to understand the concept.
Yes, thanx!
We can solve it with out multiplying on 24, making the productivity of each employee equal to 1.

So, before the epidemic there were 200*3=600 employees.
After epidemic: (200-25%*200)+(200-10%*200)+(200-100)=430
(600-430)/600=170/600=0,28333 approx 28%
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