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by jeevan.Gk » Tue Feb 24, 2009 1:57 am
Pls explain the approach...

Other than trial and error approach. And note down the time you take.
Let me know if its a question to skip.
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by sureshbala » Tue Feb 24, 2009 3:21 am
Let the population of the least district be x.

Now the maximum population of any other district is 110%(x).

Now x will be minimum if the population of the rest of the districts is maximum.

Hence for x to be minimum the population of each of the other 10 districts must be 110%(x).

Given that x + 10[110%(X)]= 132,000
i.e 12x = 132,000.
x=11,000
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by x2suresh » Tue Feb 24, 2009 3:45 am
sureshbala wrote:Let the population of the least district be x.

Now the maximum population of any other district is 110%(x).

Now x will be minimum if the population of the rest of the districts is maximum.

Hence for x to be minimum the population of each of the other 10 districts must be 110%(x).

Given that x + 10[110%(X)]= 132,000
i.e 12x = 132,000.
x=11,000
Agree with you.

Nice work
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by ven4gmat » Tue Feb 24, 2009 5:38 am
sureshbala wrote:Let the population of the least district be x.

Now the maximum population of any other district is 110%(x).

Now x will be minimum if the population of the rest of the districts is maximum.

Hence for x to be minimum the population of each of the other 10 districts must be 110%(x).

Given that x + 10[110%(X)]= 132,000
i.e 12x = 132,000.
x=11,000
ohh...you made it seem simple to me man...initially i was also a bit confused to tackle this question..
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