Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.
See classesLearn live with an expert or move at your own pace. Every option includes the complete TTP study system.
Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.
with Josh Braslow, 20+ years in test prep
Self-paced EA prep. Study on your schedule.
with
Complete access from day one. Study on your schedule.
35 cans used in 6 days to feed 10 dogsmanelgirona wrote:At a pet center 35 cans of food are used in 6 days to feed 10 dogs. Each dog is provided with the same amount of food. How many can of food would be needed fo 12 days if 3 of the dogs were sold?
a) 84
b) 70
c) 49
d) 25
e) 24
OA: C
Any ideas about how to solve it?
ajith wrote:food of dog for 1 day = 35/60manelgirona wrote:At a pet center 35 cans of food are used in 6 days to feed 10 dogs. Each dog is provided with the same amount of food. How many can of food would be needed fo 12 days if 3 of the dogs were sold?
a) 84
b) 70
c) 49
d) 25
e) 24
OA: C
Any ideas about how to solve it?
7 dogs are left now
so total cans required = 35*7*12/60 = 49 Ans C
35 cans used in 6 days to feed 10 dogs
to feed 1 dog in a day ; we have to use 35/60 cans is used
to feed 7 dogs for 12 days; we have to use 35*7*12/60 = 49 cans
My problem approach will be like this:-Diet of dog per day = 35/60 cans[In this type of problems it is better to solve by unitary method like considering for per day per dog etc.]manelgirona wrote:At a pet center 35 dogscan of food are used in 6 days to feed 10 dogs. Each dog is provided with the same amount of food. How many can of food would be needed fo 12 days if 3 of the dogs were sold?
a) 84
b) 70
c) 49
d) 25
e) 24
OA: C
Any ideas about how to solve it?
