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Target Test Prep · GMAT

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GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
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with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
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40 hours of live online classes + 6 months of TTP OnDemand
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Target Test Prep EA OnDemand

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Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

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165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
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by Jinglander » Tue Aug 03, 2010 8:19 pm
The amount of electrical current is inversely proportional to the resistance. If a wire carries 4 units of current then the resistance is cut to 1/3 of the original what is the new amount of current. Answer is 12. How can we solve this
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Source: — Problem Solving |
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by selango » Tue Aug 03, 2010 8:31 pm
C=k/R

4=K/R

C=k/(1/3*R)

C=3*k/R=3*4=12
--Anand--
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by rahul goyal » Wed Aug 11, 2010 9:59 pm
selango wrote:C=k/R

4=K/R

C=k/(1/3*R)

C=3*k/R=3*4=12
Thank you selango.we have to answer quickly in this way.
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by aarati » Wed Aug 11, 2010 10:47 pm
selango wrote:C=k/R

4=K/R

C=k/(1/3*R)

C=3*k/R=3*4=12


thank u....but ,can you explain me a bit clear ....
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