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Junior | Next Rank: 30 Posts
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by agni_mba » Sat Oct 20, 2007 12:13 pm
suyog: slight mistake in understand the question i think.

3t perimeter of triangle => area = root(3)*(t^2)/4
4s perimeter of square => area = s^2

since areas are equal as per the problem, t:s = 2/(3)^.25
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by Suyog » Sat Oct 20, 2007 3:38 pm
Thanks Dude!
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by wongee » Mon Oct 22, 2007 7:06 pm
What are the answer choices??

this means tht rt3/4t^2=s^2 correct?

Solve for t:s = 2/rt of rt3 Can someone explain how this is solved? A root of a root?

Thanks.
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by manasi_sh » Tue Oct 23, 2007 8:22 am
yes even i can't understand this root of root3 thg..plz explain
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by samirpandeyit62 » Tue Oct 23, 2007 9:15 am
I dont think we need to solve for root (root 3) simply we can write it as

(3^1/2)^1/2) = 3^1/4 or 3^.25 which ever way u put it.
Regards
Samir
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by Suyog » Tue Oct 23, 2007 9:27 am
3t perimeter of triangle, so side = t
4s perimeter of square, so side = s

As mentioned by agni_mba,

Area of the equilateral triangle is = root(3)*(t^2)/4
and
Area of the Square is = s^2

So, as per the question, the areas are equal,

root(3)*(t^2)/4 = s^2
taking root of both the sides, we get.

3^(1/4) * t / 2 = s
i.e. 3^(1/4) * t = 2s
i.e. t/s = 2 / 3^(1/4)

ratio of t to s is 2 to 3^(1/4).

KO, let us know the ans choices!
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