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Problem on Base 10

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Problem on Base 10

by f2001290 » Fri Jun 15, 2007 8:57 am
If (10^50) – 74 is written as an integer in base 10 notation, what is the sum of the digits in
that integer?
A. 424
B. 433
C. 440
D. 449
E. 467
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Re: Problem on Base 10

by gabriel » Fri Jun 15, 2007 9:12 am
f2001290 wrote:If (10^50) – 74 is written as an integer in base 10 notation, what is the sum of the digits in
that integer?
A. 424
B. 433
C. 440
D. 449
E. 467
10^50 will be 1 and 50 zeroes ... subtracting 74 from it u wuld have 48 9's and 2,6 ... that is the number wuld be 999999 .. 48times .. 26 ... so the sum of the digits will be ... 48*9+2+6= 432+8 = 440 ... ans C ..
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