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Probabilty question

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by abhi.genx7 » Fri Oct 01, 2010 11:18 am
From a group of 3 boys and 3 girls, 4 children are to be randomly selected. What is the probability that equal numbers of boys and girls will be selected?

A.1/10
B.1/2
C.4/9
D 2/3
E.3/5

Can any1 explain the method to be used to solve this problem please
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by shovan85 » Fri Oct 01, 2010 11:39 am
4 children can be selected from 6 in 6C4 ways
2 girls can be selected from 3 in 3C2 ways
2 boys can be selected from 3 in 3C2 ways

(3C2 * 3C2)/6C4 =9/15 = 3/5

IMO E
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by TheCloakedMonk » Fri Oct 01, 2010 12:01 pm
shovan85 wrote:4 children can be selected from 6 in 6C4 ways
2 girls can be selected from 3 in 3C2 ways
2 boys can be selected from 3 in 3C2 ways

(3C2 * 3C2)/6C4 =9/15 = 3/5

IMO E
I did it the exact same way.
Anything is possible if you believe in yourself and have faith in your actions.
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