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Probability - unfair coin

Expert replies
by r2kins » Thu May 12, 2011 2:10 am
The probability is 0.6 that an "unfair" coin will turn up tails on any given toss. If the coin is tossed 3 times, what is the probability that at least one of the tosses will turn up tails?

0.064
0.36
0.64
0.784
0.936
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Source: — Problem Solving |

by manpsingh87 » Thu May 12, 2011 2:31 am
r2kins wrote:The probability is 0.6 that an "unfair" coin will turn up tails on any given toss. If the coin is tossed 3 times, what is the probability that at least one of the tosses will turn up tails?

0.064
0.36
0.64
0.784
0.936
probability that at least one of the tosses will turn up tails= 1- ( none will turn up tails)

{HHH} is the only case where none of the coin will turn up tails, also probability of occurrence of head= 0.4; hence required probability is 1-(0.4)*(0.4)*(0.4)= 1-.064=0.936 hence E
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Re: Probability - unfair coin

by Scott@TargetTestPrep » Thu Jan 16, 2020 6:39 am
r2kins wrote:
Thu May 12, 2011 2:10 am
The probability is 0.6 that an "unfair" coin will turn up tails on any given toss. If the coin is tossed 3 times, what is the probability that at least one of the tosses will turn up tails?

0.064
0.36
0.64
0.784
0.936
We can use the formula:

P(At least 1 tail) = 1 - P(no tails)

P(no tails) = 0.4 x 0.4 x 0.4 = 0.064

P(at least 1 tail) = 1 - 0.064 = 0.936

Answer: E

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