Probability

1.Probability that Joshua and Jose will be selected is 1/6*1/5
(first Joshua was selected and than Jose)
You must consider the second version when fisrt Jose was selected, therefore 1/6*1/5 should be multiplied by 2.

P = Number of favourable outcomes/ total outcomes

Total outcome = chosing 2 out of 6 = 6C2 = 15

Chosing 2 out of 2 = 2C2 = 1 . (There is only one way that both Joshua and Jose can be selected)

Therefore P = 1/15


Let me try to explain in another way to

Let Joseua= J, Jose = K others be b,c,d,e
Possible selections are jk,jb,jc,jd,je, kb,kc,kd,ke, bc,bd,be ,cd,ce , de = 15
Favourable outcome of both J and K being selected .Jk are together in the above sequence only once

Therefore P = 1/15