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by SwatiDenre » Mon Jun 13, 2011 5:22 pm
10 different letters of an alphabet are given. 2 of these letters are followed by 2 digit are used to number the products of a company. IN how many ways can the products be numbered?

A. 52040
B. 8100
C. 5040
D. 1000
E. 4000


Ans - 1000


Solution?

Thanks in advance.
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by Ashley@VeritasPrep » Mon Jun 13, 2011 6:29 pm
Hi there,

Could you double-check whether the problem says followed by "2 digits" or "1 digit"?
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by smackmartine » Mon Jun 13, 2011 6:42 pm
I spent 23 min scratching my head :)
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by nafiul9090 » Mon Jun 13, 2011 8:32 pm
whats the source of the question ???
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by newgmattest » Mon Jun 13, 2011 9:12 pm
Question is correct and I assume answer is missing one "0".

Solution:

Any combination of 2 letters from 10 (where the letter can be the same one repeated) is 10x10=100 possibilities. For each of those there will be any number between 00 and 99, which is also 100 possibilities. Therefore a possible total of 100x100=10,000 products.

Otherwise for current answer, there must be only "1" digit which gives you 100 * 10 = 1000
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by SwatiDenre » Tue Jun 14, 2011 7:18 am
Ashley@VeritasPrep wrote:Hi there,

Could you double-check whether the problem says followed by "2 digits" or "1 digit"?
Hi Ashley,
it was 2 digits . I think one of our frnd has answered the question.
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by SwatiDenre » Tue Jun 14, 2011 7:19 am
newgmattest wrote:Question is correct and I assume answer is missing one "0".

Solution:

Any combination of 2 letters from 10 (where the letter can be the same one repeated) is 10x10=100 possibilities. For each of those there will be any number between 00 and 99, which is also 100 possibilities. Therefore a possible total of 100x100=10,000 products.

Otherwise for current answer, there must be only "1" digit which gives you 100 * 10 = 1000



Hi,
You are right but the answer choices was guven exactly like this.
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