let probablity of A to happen is "a"
and probability of B to happen is "b"

for two independent events A and B to happen together, probabilty is = a*b

now, we have to find if a*b>0.3

1. given a=0.25, max value of b can be, bmax=1, hence a*bmax=.25 < 0.3,
hence option 1 is sufficient to answer the ques.

2. given b=1-0.71=0.29, max value of a can be, amax=1, hence amax*b=0.29< 0.3
hence option 2 is sufficient to answer the ques.

Hence D is the answer: Both options are independently sufficient to answer the question

thanks a lot.

So can we generalize this by saying

If we have 'n' independent events the probability that all of them happening will be less than the least of the 'n' individual probabilities.

thanks

krishna

krishna kumar wrote:Hi ,

Could someone please help me to understand this problem.

If Event A and Event B are independent, is the probability that both Event A and Event B will happen greater than 0.3 ?

1. Probability that A will happen is 0.25

2. Probability that B will not happen is 0.71.

Thanks in advance.


OA D

What a question!

Here, since Event A and Event B are independent, hence the probability that both Event A and Event B will happen P (A and B)

= Probability that A will happen P (A) × Probability that B will happen P (B)

We know that 0 ≤ P (A) or P (B) ≤ 1


(1) If P (A) = 0.25, then even the greatest possible value of P (B) [i.e. P (B) = 1] would keep P (A) × P (B) always less than 0.3; thus answering a perfect NO to the stem. Sufficient

(2) Please note that P (B) = 1 - Probability that B will not happen = 1 - 0.71 = 0.29, now again, even the greatest possible value of P (A) [i.e. P (A) = 1] would keep P (A) × P (B) always less than 0.3; thus answering a perfect NO to the stem. Sufficient


[spoiler]D[/spoiler]