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3C2*(0.3)^2*(0.7) = 0.189rtaha2412 wrote:The probability that a visitor at the mall buys a pack of candy is 30%. If three visitors come to the mall today, what is the probability that exactly two visitors will buy a pack of candy?
a 0.343
b 0.147
c 0.189
d 0.063
e 0.027
P(1st visitor buys candy) = 3/10rtaha2412 wrote:The probability that a visitor at the mall buys a pack of candy is 30%. If three visitors come to the mall today, what is the probability that exactly two visitors will buy a pack of candy?
a 0.343
b 0.147
c 0.189
d 0.063
e 0.027
GMATGuruNY wrote:rtaha2412 wrote:The probability that a visitor at the mall buys a pack of candy is 30%. If three visitors come to the mall today, what is the probability that exactly two visitors will buy a pack of candy?
a 0.343
b 0.147
c 0.189
d 0.063
e 0.027
We need to determine the probability that two out of three visitors will buy a pack of candy:
P(Y-Y-N) = 0.3 x 0.3 x 0.7 = 0.063
Since there are 3 ways -- (Y-Y-N), (Y-N-Y), or (N-Y-Y) -- in which two of the three visitors can buy a pack of candy, the overall probability is 3 x 0.063 = 0.189.
Answer: C
