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by tsmith93 » Wed Mar 03, 2010 5:49 pm
A number, x, is chosen at random from the set of positive integers less than 10. What is the probability that 9/x > x?
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by papgust » Wed Mar 03, 2010 6:22 pm
You need to post only DS questions in Data Sufficiency folder. Moved this thread to "Problem Solving" folder.

Coming to the question, Plugging in numbers is the best option.

The numbers that satisfy 9/x > x condition are 1 and 2 only. Total outcomes are 9 (Positive integers less than 10)

Probability (# of outcomes / Total # of outcomes) = [spoiler]2 / 9[/spoiler]
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by tsmith93 » Wed Mar 03, 2010 6:23 pm
Sorry for posting this in the wrong folder. I'm not sure how to move it, anyone able to help me?
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by papgust » Wed Mar 03, 2010 6:26 pm
Don't worry Smith. It's already moved to appropriate folder. Just make sure that you post questions in appropriate folders in future. Thanks!
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by okletsdothis » Sat Oct 02, 2010 4:26 am
Is '0' not a positive integer to consider. Then there will be total 10 integers from 0 to 9
So should it not be 2/10 therefore 1/5 ???
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by frank1 » Sat Oct 02, 2010 4:29 am
okletsdothis wrote:Is '0' not a positive integer to consider. Then there will be total 10 integers from 0 to 9
So should it not be 2/10 therefore 1/5 ???
The defination of positive is GREATER than 0
and negative is less then 0
So 0 is neigther positive nor negative...
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by okletsdothis » Sat Oct 02, 2010 4:43 am
Got it . Thanks a ton!!
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by goyalsau » Sat Oct 02, 2010 4:53 am
frank1 wrote:
okletsdothis wrote:Is '0' not a positive integer to consider. Then there will be total 10 integers from 0 to 9
So should it not be 2/10 therefore 1/5 ???
The defination of positive is GREATER than 0
and negative is less then 0
So 0 is neigther positive nor negative...
I would like to add one thing to ZERO
that zero is an even integer.
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