BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Probability

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 328
Joined: Thu Aug 07, 2008 5:25 pm
Location: Philadelphia
Thanked: 4 times
GMAT Score:550
by Abdulla » Sun Jul 12, 2009 7:40 pm
A certain school has 50 students assigned randomly to 5 distinct classes, and each student is assigned to only one class. If the numbers of students in the classes are consecutive, what is the probability that a given student is in one of the two largest classes?

(A) 48%
(B) 46%
(C) 42%
(E) 38%
(D) 34%
Abdulla
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
User avatar
Master | Next Rank: 500 Posts
Posts: 170
Joined: Tue May 26, 2009 12:00 pm
Thanked: 5 times

by yogami » Sun Jul 12, 2009 8:30 pm
Well, first of all it says that 50 students are randomly distributed in the class and no student takes two classes. So this makes our lives easier (will not involve the whole set theory drama). Secondly it also says that number of students are consecutive over the classes. So only one consecutive sequence fits the breakdown (8,9,10,11,12). Now the odds of picking a student from the two largest classes i,e from the classes with counts 11 and 12 are (11 + 12)/50
so 23/50 which is 46%
200 or 800. It don't matter no more.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Newbie | Next Rank: 10 Posts
Posts: 9
Joined: Sat May 02, 2009 7:24 pm

Concur

by uw490 » Mon Jul 13, 2009 1:07 pm
Agreed. I also got 46%, B...
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 8177
Joined: Sat Apr 25, 2015 10:56 amFollowed by: 29 members
Location: Los Angeles, CA
Thanked: 43 times

by Scott@TargetTestPrep » Sun May 19, 2019 6:30 pm
Abdulla wrote:A certain school has 50 students assigned randomly to 5 distinct classes, and each student is assigned to only one class. If the numbers of students in the classes are consecutive, what is the probability that a given student is in one of the two largest classes?

(A) 48%
(B) 46%
(C) 42%
(E) 38%
(D) 34%
Since the average number of students per class is 50/5 = 10 and the the number of students in the 5 classes are consecutive numbers, then the number of students in the 5 classes are 8, 9, 10, 11 and 12. Thus, the probability that a given student is in one of the two largest classes is:

(11 + 12)/50 = 23/50 = 46/100 = 46%

Answer: B

Scott Woodbury-Stewart
Founder and CEO
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews

ImageImage
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1