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probability

Expert replies
by ketkoag » Wed Jun 10, 2009 9:27 am
What is the total number of some green balls and yellow balls?
1) The probability that a ball randomly selected is green is 1/10
2) One green ball picked out at fist, the probability that another ball randomly selected is green is 3/8.

[spoiler]please confirm the answer, IMO : E[/spoiler]
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Source: — Data Sufficiency |

by Musiq » Wed Jun 10, 2009 9:32 am
Ketkoag,

May I ask where you got this question from....it's not very GMAT-like.

The answer is E, because there could be other colors of balls present...no where are we told that the only two kinds of balls are Green and Yellow.
For love, not money.
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by ankit1383 » Mon Aug 10, 2009 6:06 am
IMO...C
can someone confirm....(If we assume there are only two types of ball)
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by aspiregmat » Mon Aug 10, 2009 6:39 am
If no other information given about other color balls its definately E.

Lets assume that there are only green and yellow balls:

1) Probability of picking a green ball = 1/10 so only thing we know is green:yellow = 1:9

2) Probability of picking a green ball in second try = 3/8 and 1 green is already out so green:yellow = 4:5 or 7:9 and so on...

combining both == again only ratios which are also not matching...

So IMO E even if we assume only green and yellow balls.
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by ankit1383 » Mon Aug 10, 2009 6:55 am
Let the ratio be x:9x from statement 1

From second statement
(x/10x)* (x-1)/(10x-1)=3/8 (since both times green ball selected)

we can solve this...

where m i getting ths wrong
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by aspiregmat » Mon Aug 10, 2009 7:16 am
2) One green ball picked out at fist, the probability that another ball randomly selected is green is 3/8.

It does not say that the probability of picking two green balls is 3/8. It gives the probability of only the second ball.

Even if we take that.... the green and yellow balls will come in fraction which doesn't looks logical. IMO though not sure...
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