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is P(F&E) not equal to P(E) * P(F)?scoobydooby wrote:probability that event E or event F or both will occur=>probability atleast 1 of them will occur: p(EUF)=p(E)+p(F)-P(F and E)
1) gives only p(E). not. sufficient.
2) gives only p(F). not sufficient
together, we do not have P(F and E). so both together not sufficien
E
and in this case, we do not know whether the events are independent or not, correct?scoobydooby wrote:P(F&E) = P(E) * P(F) only when E and F are independent events, ie the out come of one event is not dependent on the outcome of the other.
yes, thats right. no information on the nature of the events.apple100 wrote:and in this case, we do not know whether the events are independent or not, correct?scoobydooby wrote:P(F&E) = P(E) * P(F) only when E and F are independent events, ie the out come of one event is not dependent on the outcome of the other.
