vaibhav101 wrote:the probability that a teacher will give a surprise test during any class meeting is 1/5. If a student is absent on 2 days, then the probability that he will miss at least 1 test is.
A 24/25
B 1/25
C 16/25
D 9/25
E 7/25
First, if P(test) = 1/5, then p(NO test) = 1 - 1/5 =
4/5
NOTE: questions with
"at least" are often great candidates for using the complement.
That is: P(Event A occurs) = 1 - P(Event A does not occur)
So, P(miss at least 1 test) = 1 -
P(miss no tests)
P(miss no tests)
P(miss no tests) = P(no test on day 1
AND no test on day 2)
= P(no test on day 1)
X P(no test on day 2)
= (4/5)
X (4/5)
=
16/25
So, P(miss at least 1 test) = 1 -
P(miss no tests)
= 1 -
16/25
= 9/25
Answer: D
Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
