Following Questions can be found on Pg 93 of Manhattan GMAT Word Translation Guide
1) A florist has 2 azaleas, 3 buttercups, 4 petunias. She puts two flowers together at random bouquet. However, the customer calls and says that she does not want two of the same flower. What is the probability that the florist does not have to change the bouguet? If anyone can walk me through this problem step by step very slowly, infact pretend im an actuall idiot, cause I dont even get the explanation provided by the guide on this problem!
2) Obriviated version. 5 actresses: A, B, C, D, E, F to be selected to star in a movie. There are 3 spaces. What are the chances that both A and B will star together. On this one I get o the point where its 1/20 chance, but I dont get why it has to be multiplied by 6. We already know that for the two to be selected together the odds are 1/20 is this now what the problem is asking? The answer is 1/20 (6)=3/10 since there are 6 ways to arrange the outcome when A and B are together.
1) A florist has 2 azaleas, 3 buttercups, 4 petunias. She puts two flowers together at random bouquet. However, the customer calls and says that she does not want two of the same flower. What is the probability that the florist does not have to change the bouguet? If anyone can walk me through this problem step by step very slowly, infact pretend im an actuall idiot, cause I dont even get the explanation provided by the guide on this problem!
2) Obriviated version. 5 actresses: A, B, C, D, E, F to be selected to star in a movie. There are 3 spaces. What are the chances that both A and B will star together. On this one I get o the point where its 1/20 chance, but I dont get why it has to be multiplied by 6. We already know that for the two to be selected together the odds are 1/20 is this now what the problem is asking? The answer is 1/20 (6)=3/10 since there are 6 ways to arrange the outcome when A and B are together.
