nehatandon wrote:A certain dice game can only be won if, when a player throws two fair six-sided dice, the number showing on one of the dice
is a multiple of the number showing on the other. What is the probability that a player wins this game?
(A)11/18
(B)11/36
(C)1/4
(D)2/9
(E)7/36

Here are the ways in which a player can win

1st dice------------ 2nd dice
1------------ 1,2,3,4,5,6
2------------ 1,2,4,6
3------------ 1,3,6
4------------ 1,2,4
5------------ 1,5
6------------ 1,2,3,6

Favorable no. of outcomes = 6+4+3+3+2+4 = 22
Total no. of outcomes = 6*6 = 36

So, required probability = 22/36 = 11/18 A

is one a multiple of every number?

Ramit88 wrote:is one a multiple of every number?

Nope, but every no. is multiple of one. If you get (say) no. 2 on the 1st dice and no. 1 on 2nd dice, still you win. (As the number showing on one of the dice is still a multiple of number showing on the other).