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by chaitanya.mehrotra » Fri Jul 29, 2011 6:42 am
A florist has 2 azaleas, 3 buttercups, and 4 petunias. She puts two flowers together at
random in a bouquet. However, the customer calls and says that she does not want
two of the same flower. What is the probability that the florist does not have to
change the bouquet?
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Source: — Problem Solving |

by sunnyjohn » Fri Jul 29, 2011 7:17 am
Answer: Total number of arrangement - Arrangement not required.

Total no of arrangement: 9(C)2 ==> 36
Arrangement not required: 3(C)2 + 2(C)2 + 4(C)2 => 3 + 1 + 6 = 10

Answer: 36 - 10 = 26/36 => 13/18
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