hypotenuse = a
each side = a/root(2)
Perimeter of rt isosceles triangle = a + 2a/root(2) = a+a*root(2) = 16+16*root(2)
so hypotenuse = 16
Option B
BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course
Redeem
Target Test Prep GMAT OnDemand
Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.
- 715+ score guarantee — highest in the industry (99th percentile)
- 52 chapters · 1,500+ lessons · 4,000+ practice questions
- 400 hours of video · 1,500+ instructor-led HD smartboard lessons
- 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
- 24/7 live support + weekly Zoom office hours with GMAT instructors
- TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
- 1,200+ flashcards + AI-powered study assistant & daily calendar
- OnDemand, LiveTeach & GMAT Bootcamp formats available
- Also: GRE, SAT Math & Executive Assessment courses
- MBA Admissions Consulting now available
- 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
- 200,000+ students served
- 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★
5.0
(559 reviews)
130-pt guarantee
$0 to start
then $127/mo
Any Idea?
Source: Beat The GMAT — Problem Solving |
The easiest way is to plug the answer choices [ remember to start with smart choices ]
2a^2 = b^2 (b is the hypotenuse)
or, a = b/sqrt(2) = b*sqrt(2)/2 -- THIS IS OUR MAIN EXPRESSION.
By smart choices I mean -- look at the perimeter.. It has root2 in it. So start with choices where you don't have ROOT(2) because our expression above has already got one.
Put the choices and see whether the value satisfies this equation .. 2a+b = 16+16*sqrt(2).
this will take 45-60 secs.
hth
IMO [spoiler](16) [/spoiler] the correct answer.
2a^2 = b^2 (b is the hypotenuse)
or, a = b/sqrt(2) = b*sqrt(2)/2 -- THIS IS OUR MAIN EXPRESSION.
By smart choices I mean -- look at the perimeter.. It has root2 in it. So start with choices where you don't have ROOT(2) because our expression above has already got one.
Put the choices and see whether the value satisfies this equation .. 2a+b = 16+16*sqrt(2).
this will take 45-60 secs.
hth
IMO [spoiler](16) [/spoiler] the correct answer.
2a^2=h^2
a=h/sqroot2
2*h/sqroot2+h=16+16*sqroot2
sqroot2*h+h=16+16*sqroot2
h*(sqroot2+1)=16(sqroot2+1)
h=16
a=h/sqroot2
2*h/sqroot2+h=16+16*sqroot2
sqroot2*h+h=16+16*sqroot2
h*(sqroot2+1)=16(sqroot2+1)
h=16
If OA is A, IMO B
If OA is B, IMO C
If OA is C, IMO D
If OA is D, IMO E
If OA is E, IMO A
FML!! :/
If OA is B, IMO C
If OA is C, IMO D
If OA is D, IMO E
If OA is E, IMO A
FML!! :/
Let the length of the perpendicular sides be a, Hypotenuse = a*Square root(2) = ?
16 + 16*(Square root(2)) = a+a+(a*Square root(2))
16*(1+(Square root(2)) = a*Square root(2)* (1+(Square root(2))
16 = a*Square root(2) = Hypotenuse !
IMO : B
vaibhavgupta - I reckon you calculated the side, and not the Hypotenuse
16 + 16*(Square root(2)) = a+a+(a*Square root(2))
16*(1+(Square root(2)) = a*Square root(2)* (1+(Square root(2))
16 = a*Square root(2) = Hypotenuse !
IMO : B
vaibhavgupta - I reckon you calculated the side, and not the Hypotenuse
Anil Gandham
Welcome to BEATtheGMAT | Photography | Getting Started | BTG Community rules | MBA Watch
Check out GMAT Prep Now's online course at https://www.gmatprepnow.com/
Welcome to BEATtheGMAT | Photography | Getting Started | BTG Community rules | MBA Watch
Check out GMAT Prep Now's online course at https://www.gmatprepnow.com/
neelgandham wrote:Let the length of the perpendicular sides be a, Hypotenuse = a*Square root(2) = ?
16 + 16*(Square root(2)) = a+a+(a*Square root(2))
16*(1+(Square root(2)) = a*Square root(2)* (1+(Square root(2))
16 = a*Square root(2) = Hypotenuse !
IMO : B
vaibhavgupta - I reckon you calculated the side, and not the Hypotenuse
Hmm.. will keep this in mind, thanks
If OA is A, IMO B
If OA is B, IMO C
If OA is C, IMO D
If OA is D, IMO E
If OA is E, IMO A
FML!! :/
If OA is B, IMO C
If OA is C, IMO D
If OA is D, IMO E
If OA is E, IMO A
FML!! :/













