hypotenuse = a
each side = a/root(2)
Perimeter of rt isosceles triangle = a + 2a/root(2) = a+a*root(2) = 16+16*root(2)
so hypotenuse = 16
Option B
Any Idea?
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saketk
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The easiest way is to plug the answer choices [ remember to start with smart choices ]
2a^2 = b^2 (b is the hypotenuse)
or, a = b/sqrt(2) = b*sqrt(2)/2 -- THIS IS OUR MAIN EXPRESSION.
By smart choices I mean -- look at the perimeter.. It has root2 in it. So start with choices where you don't have ROOT(2) because our expression above has already got one.
Put the choices and see whether the value satisfies this equation .. 2a+b = 16+16*sqrt(2).
this will take 45-60 secs.
hth
IMO [spoiler](16) [/spoiler] the correct answer.
2a^2 = b^2 (b is the hypotenuse)
or, a = b/sqrt(2) = b*sqrt(2)/2 -- THIS IS OUR MAIN EXPRESSION.
By smart choices I mean -- look at the perimeter.. It has root2 in it. So start with choices where you don't have ROOT(2) because our expression above has already got one.
Put the choices and see whether the value satisfies this equation .. 2a+b = 16+16*sqrt(2).
this will take 45-60 secs.
hth
IMO [spoiler](16) [/spoiler] the correct answer.
- vaibhavgupta
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If OA is A, IMO B
If OA is B, IMO C
If OA is C, IMO D
If OA is D, IMO E
If OA is E, IMO A
FML!! :/
If OA is B, IMO C
If OA is C, IMO D
If OA is D, IMO E
If OA is E, IMO A
FML!! :/
- neelgandham
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Let the length of the perpendicular sides be a, Hypotenuse = a*Square root(2) = ?
16 + 16*(Square root(2)) = a+a+(a*Square root(2))
16*(1+(Square root(2)) = a*Square root(2)* (1+(Square root(2))
16 = a*Square root(2) = Hypotenuse !
IMO : B
vaibhavgupta - I reckon you calculated the side, and not the Hypotenuse
16 + 16*(Square root(2)) = a+a+(a*Square root(2))
16*(1+(Square root(2)) = a*Square root(2)* (1+(Square root(2))
16 = a*Square root(2) = Hypotenuse !
IMO : B
vaibhavgupta - I reckon you calculated the side, and not the Hypotenuse
Anil Gandham
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- vaibhavgupta
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neelgandham wrote:Let the length of the perpendicular sides be a, Hypotenuse = a*Square root(2) = ?
16 + 16*(Square root(2)) = a+a+(a*Square root(2))
16*(1+(Square root(2)) = a*Square root(2)* (1+(Square root(2))
16 = a*Square root(2) = Hypotenuse !
IMO : B
vaibhavgupta - I reckon you calculated the side, and not the Hypotenuse
Hmm.. will keep this in mind, thanks
If OA is A, IMO B
If OA is B, IMO C
If OA is C, IMO D
If OA is D, IMO E
If OA is E, IMO A
FML!! :/
If OA is B, IMO C
If OA is C, IMO D
If OA is D, IMO E
If OA is E, IMO A
FML!! :/













