Hi shashwats,
I hope this is your question - what is the probability of getting a 2 and a 3 when 2 numbers are randomly picked from the set {1,2,3,4,5}. If yes, then here's the solution.
1. The basic counting would give you 20 total possible combinations (remember - (2,3) and (3,2) are different).
Hence you would have 2/20 as your probability.
2. Using formula, it would be 2C2 / 5C2.
You might want to note this.
There might rarely be a situation wherein you would require a combination in the numerator and a permutation in the denominator.
Pls hit 'thank' button if you find my post useful.
Probability basics
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vivekchandrams
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kul512
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I think yiu are confused between two question-
1. How many ways to select two number?
2. what is the probavility that those two selected numbers are 2 and 3?
for 1st question simple answer is 5C2, that is 10. That means if you take two nubers at a time you can mame 10 different selection.
For 2nd question -
you want pair of 2 and 3, so your probability that this one particular pair is chosen out of 10 is 1/10 that is 1/5C2= desired case/total cases.
I think its clear.
1. How many ways to select two number?
2. what is the probavility that those two selected numbers are 2 and 3?
for 1st question simple answer is 5C2, that is 10. That means if you take two nubers at a time you can mame 10 different selection.
For 2nd question -
you want pair of 2 and 3, so your probability that this one particular pair is chosen out of 10 is 1/10 that is 1/5C2= desired case/total cases.
I think its clear.
Sometimes there is very fine line between right and wrong: perspective.
