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by Gurpinder » Thu Jul 29, 2010 1:33 pm
A certain bag contains red, blue, yellow, and green marbles. If a marble is randomly drawn from the bag, the probability of drawing a blue marble is .2, the probability of drawing a red marble is .3, and the probability of drawing a yellow marble is .1. What is the probability of drawing a green marble?

oa: .4
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by nithi_mystics » Thu Jul 29, 2010 1:57 pm
p(R)+p(B)+p(Y)+p(G) = 1

.3 + .2 + .1 + p(G) = 1

==> p(G) = 0.4
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by Gurpinder » Thu Jul 29, 2010 1:59 pm
nithi_mystics wrote:p(R)+p(B)+p(Y)+p(G) = 1

.3 + .2 + .1 + p(G) = 1

==> p(G) = 0.4

ahh.....silly mistake again....today is a bad day :( ....


thanks nithi
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by indiantiger » Sun Aug 01, 2010 2:17 pm
total probability of all the events is never greater than 1

probability of green marble = 1 - 0.1 - 0.2 - 0.3 = 0.4
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