Α computer wholesaler sells eight different computers and each is priced differently. If the wholesaler chooses three computers for display at a trade show, what is the probability (all things being equal) that the two most expensive computers will be among the three chosen for display?
A.15/36 B.3/28 C.1/28 D.1/56 E.1/168
The official answer is B - I cannot understand the logic behind it though. What I was doing was the below - unfortunately is incorrect!
8!/3!*5!=56
3!/2!*1!=3
and then favourite outcomes / total number of outcomes => 3/56
A.15/36 B.3/28 C.1/28 D.1/56 E.1/168
The official answer is B - I cannot understand the logic behind it though. What I was doing was the below - unfortunately is incorrect!
8!/3!*5!=56
3!/2!*1!=3
and then favourite outcomes / total number of outcomes => 3/56
