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by divya23 » Thu Jun 02, 2011 9:42 pm
cake manufacture of cake, muffin and bread has 100 buyers
50 purchase cakes
40 = muffin
and 20 = cake and muffin both
if a buyer is to be selected form 100 buyers what is the probability that the buyer selected will be one hu purchases neither cake nor muffin
1/10
3/10
1/2
7/10
9/10

3/10
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by Anurag@Gurome » Thu Jun 02, 2011 9:50 pm
Number of buyers who purchases only cake = C = (50 - 20) = 30
Number of buyers who purchases only muffin = M = (40 - 20) = 20
Number of buyers who purchases both of them = CM = 20
Number of buyers who purchases neither of them = N

Now, total number of buyers = (C + M + CM + N) = 100

Hence, N = 100 - (C + M + CM) = 100 - (30 + 20 + 20) = 30

Required Probability = 30/100 = 3/10

The correct answer is B.
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by cans » Thu Jun 02, 2011 9:59 pm
total 100
c=50
m=40
both=20
Thus only cake=50-20=30
only muffin = 40-20=20
total = only cake + only muffin + both + none
=> none = 100-30-20-20 = 30
prob = 30/100 = 3/10
IMO B
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