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by majorsheetal » Fri Oct 01, 2010 1:25 am
If x and Y are integers and x^2 = y and y^2 = 27 x and xy = 27 than what is the value of x-y=?


I am feeling very demoralised that i am not even able to solve this easy problem . It looks so simple but still....

any solution please?
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by kvcpk » Fri Oct 01, 2010 1:36 am
majorsheetal wrote:If x and Y are integers and x^2 = y and y^2 = 27 x and xy = 27 than what is the value of x-y=?


I am feeling very demoralised that i am not even able to solve this easy problem . It looks so simple but still....

any solution please?
xy = 27 and x^2 = y
Replace y with x^2

x^3 = 27
implies x= 3

now x^2 = y
Hence y = 9

x-y = 9-3 = 6.

Hope this helps!!
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by majorsheetal » Fri Oct 01, 2010 1:47 am
Thanks !! it was so simple..and i spent hell lot of a time to solve it....
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by pzazz12 » Fri Oct 01, 2010 2:43 am
kvcpk wrote:
majorsheetal wrote:If x and Y are integers and x^2 = y and y^2 = 27 x and xy = 27 than what is the value of x-y=?


I am feeling very demoralised that i am not even able to solve this easy problem . It looks so simple but still....

any solution please?
xy = 27 and x^2 = y
Replace y with x^2

x^3 = 27
implies x= 3

now x^2 = y
Hence y = 9

x-y = 9-3 = 6.

Hope this helps!!

thank u......
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