If n = p + r, where n, p, and r are positive integers and n is odd, does p equal 2?
(1) p and r are prime numbers.
(2) r ≠ 2
IMO B
OA is C
(1) p and r are prime numbers.
(2) r ≠ 2
IMO B
OA is C
From the question stem, n = odd. the only possibility of n = O would be if it was E + O or O+ E.sanjib wrote:If n = p + r, where n, p, and r are positive integers and n is odd, does p equal 2?
(1) p and r are prime numbers.
(2) r ≠ 2
IMO B
OA is C
1) insufficient. the only even prime number is 2. but that doesn't mean p could equal 2. r could also equal 2.
for ex; 2+3 = 5 (n)----> p+r
or for ex; 3+2 = 5---> p+r
2) is obviously Insufficient. p = 2, r = 5, or p = 4 r = 5
together: both are prime numbers and r is not equal to 2.
which means p = 2 and r = Odd number.
sufficient. (C)
