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Prime Number

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Source: — Problem Solving |

by Brent@GMATPrepNow » Sat May 05, 2012 5:52 am
GmatKiss wrote:If 3 < x < 100,for how many values of x/3 is the square of a prime number?

A.2
B.3
C.4
D.5
E.9
Let's begin by listing some prime numbers: 2, 3, 5, 7, 11, 13 . . .
So, some squares of prime numbers: 2^2, 3^2, 5^2, 7^2, 11^2 . . .
When we evaluate each one, we get 4, 9, 25, 49, 121,...

- For x/3 to equal 4, x must equal 12
- For x/3 to equal 9, x must equal 27
- For x/3 to equal 25, x must equal 75
- For x/3 to equal 49, x must equal a number greater than 100. Since we're told that x<100, we can stop and conclude that there are 3 values of x such that x/3 is the square of a prime number

So, the answer is B

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by LalaB » Sat May 05, 2012 7:27 am
3 < x < 100

1<X/3<100/3

SO, WE HAVE 3 OPTIONS-
3*2^2
3*3^2
3*5^2
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by GMAT Kolaveri » Sat May 05, 2012 9:39 am
x/3 = square of prime no
multiply by 3 both sides.

x= 3 *( square of prime no i.e 4,9,25,)


product of x and sq of prime no should be less than 100. only 3 products satisfy this condition

3 * 4
3 * 9
3 * 25

3 * 7 > 100
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