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by moneyman » Thu Nov 20, 2008 4:55 am
Is it E ?
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Source: — Data Sufficiency |
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by gmat009 » Thu Nov 20, 2008 7:27 am
I am getting C
Value of n=63
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by logitech » Thu Nov 20, 2008 8:39 am
gmat009 wrote:I am getting C
Value of n=63
Because you are missing 13.
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by gmat009 » Thu Nov 20, 2008 9:24 am
logitech wrote:
gmat009 wrote:I am getting C
Value of n=63
Because you are missing 13.
yes you are right........
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by 4meonly » Thu Nov 20, 2008 9:52 am
logitech wrote:
gmat009 wrote:I am getting C
Value of n=63
Because you are missing 13.
(2)
n=20q +3
if n=13, then q=0,5

is it possible for q to be 0,5?

I never encountered such values for quotent in remainder questions...
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by vishubn » Thu Nov 20, 2008 9:57 am
n/25=a+13 ---given

A)so n=a*25+13 which says 25a is multilple of 25

n=38,63,88 Insuff

B)n>20 but the end limit is not given ! Insuff

Togethere we know n>20 and n <100

still the numbers 38,63,88 holds good

OA E

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by logitech » Thu Nov 20, 2008 9:58 am
4meonly wrote:
logitech wrote:
gmat009 wrote:I am getting C
Value of n=63
Because you are missing 13.
(2)
n=20q +3
if n=13, then q=0,5

is it possible for q to be 0,5?

I never encountered such values for quotent in remainder questions...
First of all, it is 25 not 20

N= 25q+13

q=0,1,2,3, ..etc

Remember 12 divided by 38 , and the remainder is 12

or if X<Y and X is divided by Y

The remainder is X itself. Put that in a flash card, I DID! ;-)
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by 4meonly » Thu Nov 20, 2008 10:09 am
logitech,
I think you misunderstood me

I am refering to Stem 2
(2)
n=20q +3
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by cramya » Thu Nov 20, 2008 10:12 am
I think the OA is C)

n=63

13/20 does not give a remainder of 3.
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by mals24 » Thu Nov 20, 2008 10:34 am
One more vote for C.

n = 25a+13

1: n<100

n could be 38, 63, 88.

2: n = 20b+3

Insuff

Combining you'll get

n = 63, as 38 and 88 when divided by 20 do not leave a remainder of 3
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by logitech » Thu Nov 20, 2008 10:43 am
I guess I am on drugs...It is C
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by cramya » Thu Nov 20, 2008 2:46 pm
I guess I am on drugs...It is C
Dont sweat ;it happens to all of us. I remember blaberring on one of the remainder posts :-)
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