BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Powerprep Geometry

Expert replies
by caramel3536 » Sat May 03, 2008 1:18 pm
May someone help me with this question:

A rectangular box is 10 inches wide, 10 inches long, and 5 inches high. What is the greatest possible (straight-line) distance in inches between any two points on the box (ans 15)
Join the discussion
Source: — Problem Solving |

by sripardhu » Sat May 03, 2008 2:46 pm
= sqrt((sqrt(10 ^ 2 + 10 ^ 2)) ^ 2 + 5 ^ 2)

= 15
Join the discussion

by AleksandrM » Sat May 03, 2008 4:47 pm
I think that everyone should use the visualization principle, and draw first [see my attachement - the dotted line in the second box, is one of the sides that you would view when you turn the box to see the inside triangle as it would appear in a two-dimensional space].

Realize that you need to get the length of the line from one angle to the furthest opposite angle of the box.

You now have a triangle with a known height, but an unknown base and hypotenuse. The base and the two sides measuring 10, form a lying right triangle. By calculating the hypotenuse of the lying triangle, you will calculate the base of the bigger triangle inside the box.

10^2 + 10^2 = h^2

h = 10sqroot2 -------> this is the base of the bigger triangle.

Note: you don't have to go through this calculation if you memorize the common triangles, which will lead you to recognize that this equilateral triangle has sides in the ratio of x : x : xsqroot2

Now, go on to get your answer:

(10sqroot2)^2 + 5^2 = x^2 [the new hypotenuse]

200 + 25 = x^2 take a sqroot of both sides

x = 15
Attachments
two triangles.doc
(23.5 KiB) Downloaded 108 times
Join the discussion

Thanks guys!

by caramel3536 » Sun May 04, 2008 1:37 pm
.........
Join the discussion