power prep question

jc114 wrote:In a survey of students, each student selected from a list of 12 songs the 2 songs that the student liked the best. If each song was selected 4 times, how many students were surveyed?

A. 96
B. 48
C. 32
D. 24
E. 18

12 songs selected 4 times = total of 48 songs.

Each student selects 2 songs. Hence total number of students
= 48/2 = 24

Is it D?

wrote: Which of the following inequalities has a solution set that, when graphed on the number line, is a single segment of finite length?

A. x^4 >= 1
B. c^3 <= 27
C. X^2 >- 16
D. 2<= |x|<=5
E. 2<=3x-4<=6

Hmm, "finite" length seems to the main clue here

A - Just taking positive values of x, x >= 1 which is an infinite line

B - c <= 3. Again infinite line

C - imaginary values?

D - For positive values of x, 2 <= x <= 5 (bounded line).
For negative values of x, x < -2 and x > -5 (bounded line)
But this is not a single segment

E - 3x-4 >= 2 implies x >= 2.
3x-4 <= 6 implies x <= 10/3.
This is a single line that is bounded to limits

I'm going to go with E.

OA please.

I got D too for the first Q, but doesn't that seem too easy?!

I got D for the first one. If each song was selected twice, and there were 2 songs to chose from, that means that there were a total of 48 picks. But since they have to be in pairs of 2, you have to divide 48 by 2, so I got 24. This sounds wrong though because it seems too few...

In a survey of students, each student selected from a list of 12 songs the 2 songs that the student liked the best. If each song was selected 4 times, how many students were surveyed?

A. 96
B. 48
C. 32
D. 24
E. 18

12 songs... and each song is selected 4 times....Thus there are 4*12 = 48 selections

Since each student makes 2 selections....there were 24 students


Which of the following inequalities has a solution set that, when graphed on the number line, is a single segment of finite length?

A. x^4 >= 1
B. c^3 <= 27
C. X^2 >- 16
D. 2<= |x|<=5
E. 2<=3x-4<=6