4-1 = 3

3^2 = 9

3-2 = 1

2^9/2^1 = 2^8 A

karthikpandian19 wrote:

Question i have attached IMAGE.refer ......

(2^((4-2)^2))/2^(3-2)

2^8
2^7
2^6
2^5
2^4

karthikpandian19 wrote:

Question i have attached IMAGE.refer ......

(2^((4-2)^2))/2^(3-2)

2^8
2^7
2^6
2^5
2^4

(4-1)^2=3^2=9
2^9/2^(3-2)=2^9/2^1= 2^8

your power for 2 IS (4-1)^2 -(3-2) = 8
hence 2^8

Maybe a simple answer for you, but i am confused here with the Power exponents rules. Can you clarify the below:

2^((4-1)^2)
derives 2^(3^2)

Can't it be further simplified as 8^2 (which means first work for 2^3 and then for the ^2 of it)

I feel lost somewhere with the equations.....Pls clarify

I mean why this rule is not used...

shankar.ashwin wrote:4-1 = 3

3^2 = 9

3-2 = 1

2^9/2^1 = 2^8 A

karthikpandian19 wrote:

Question i have attached IMAGE.refer ......

(2^((4-1)^2))/2^(3-2)

2^8
2^7
2^6
2^5
2^4

Hi Karthik,

A basic arithmetic rule is to always work with quantities inside the bracket first and then move on simplifying further.

Look up basic BODMAS rules with brackets, as a rule always compute quantities inside the bracket.


SO here, 2^(3^2) = 2^9 because (3^2) is inside the bracket and considered a single entity.

Thank you for the clarification

shankar.ashwin wrote:Hi Karthik,

A basic arithmetic rule is to always work with quantities inside the bracket first and then move on simplifying further.

Look up basic BODMAS rules with brackets, as a rule always compute quantities inside the bracket.


SO here, 2^(3^2) = 2^9 because (3^2) is inside the bracket and considered a single entity.