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Source: — Data Sufficiency |

by Maciek » Fri Sep 17, 2010 3:25 pm
Hi!

IMO E

x^2*y > 0 ?
x^2*y > 0 if y > 0 and (x < 0 or x > 0 )

(1) y^2 > 0
Therefore, y < 0 or y > 0
Statement (1) ALONE is INSUFFICIENT
(2) x = 2
Statement (2) ALONE is INSUFFICIENT
Statements (1) & (2) BOTH are together INSUFFICIENT.

Hope it helps!
Best,
Maciek
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by sumit.sinha » Sat Sep 18, 2010 4:26 am
Gurpinder wrote:Image

doesent (1) mean y= +.

thx.
No y^2 >0 does not mean y is +ve.
Consider it this way,
y*y = +ve
so, -ve * -ve = +ve and also +ve * +ve = +ve.
So y can be either -ve or +ve.
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by Gurpinder » Sat Sep 18, 2010 8:29 am
I assumed something silly.

I read somewhere that when a questions asks you whether --> y^2>0, is y positive. all this is asking you is is y>0.

I misapplied this here!

I see why (E) is the right answer.

Just a little doubt, can you guys clarify what the questions means when it says x*y is defined as X^2*y

Thx.
"Do not confuse motion and progress. A rocking horse keeps moving but does not make any progress."
- Alfred A. Montapert, Philosopher.
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by sumit.sinha » Sat Sep 18, 2010 8:52 am
Gurpinder wrote:I assumed something silly.

I read somewhere that when a questions asks you whether --> y^2>0, is y positive. all this is asking you is is y>0.

I misapplied this here!

I see why (E) is the right answer.

Just a little doubt, can you guys clarify what the questions means when it says x*y is defined as X^2*y

Thx.
It is function question.
it says x*y is defined as x^2*y.
i.e. if x=2 and y=3 then 2*3 value will be 2^2*3 = 12 even tough 2*3 (in real world)=6.
Cheers,
Sumit
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by Gurpinder » Sat Sep 18, 2010 9:25 am
sumit.sinha wrote:
Gurpinder wrote:I assumed something silly.

I read somewhere that when a questions asks you whether --> y^2>0, is y positive. all this is asking you is is y>0.

I misapplied this here!

I see why (E) is the right answer.

Just a little doubt, can you guys clarify what the questions means when it says x*y is defined as X^2*y

Thx.
It is function question.
it says x*y is defined as x^2*y.
i.e. if x=2 and y=3 then 2*3 value will be 2^2*3 = 12 even tough 2*3 (in real world)=6.
Oh man. I need some Coffee.

Thx Sumit.
"Do not confuse motion and progress. A rocking horse keeps moving but does not make any progress."
- Alfred A. Montapert, Philosopher.
Join the discussion

by sumit.sinha » Sat Sep 18, 2010 9:38 am
Gurpinder wrote:
sumit.sinha wrote:
Gurpinder wrote:I assumed something silly.

I read somewhere that when a questions asks you whether --> y^2>0, is y positive. all this is asking you is is y>0.

I misapplied this here!

I see why (E) is the right answer.

Just a little doubt, can you guys clarify what the questions means when it says x*y is defined as X^2*y

Thx.
It is function question.
it says x*y is defined as x^2*y.
i.e. if x=2 and y=3 then 2*3 value will be 2^2*3 = 12 even tough 2*3 (in real world)=6.
Oh man. I need some Coffee.

Thx Sumit.
Yeah they look a little awkward first time around.
Hey, why is your target score 900+ :P . i think the exam is out of 800. lol
Cheers,
Sumit
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by Gurpinder » Sat Sep 18, 2010 9:53 am
sumit.sinha wrote:
Gurpinder wrote:
sumit.sinha wrote:
Gurpinder wrote:I assumed something silly.

I read somewhere that when a questions asks you whether --> y^2>0, is y positive. all this is asking you is is y>0.

I misapplied this here!

I see why (E) is the right answer.

Just a little doubt, can you guys clarify what the questions means when it says x*y is defined as X^2*y

Thx.
It is function question.
it says x*y is defined as x^2*y.
i.e. if x=2 and y=3 then 2*3 value will be 2^2*3 = 12 even tough 2*3 (in real world)=6.
Oh man. I need some Coffee.

Thx Sumit.
Yeah they look a little awkward first time around.
Hey, why is your target score 900+ :P . i think the exam is out of 800. lol
lol.... just having fun =)
"Do not confuse motion and progress. A rocking horse keeps moving but does not make any progress."
- Alfred A. Montapert, Philosopher.
Join the discussion