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Positive integer

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Source: — Problem Solving |

by Anurag@Gurome » Sun Sep 18, 2011 8:25 pm
Solution:
Check each option one by one.
Take a).
f(a+b) = (a+b)^2 = a^2 + 2ab + b^2 where as f(a) + f(b) = a^2 + b^2.
So,a) is ruled out.
Take b).
f(a+b) = a + b + 1 where as f(a) + f(b) = a + 1 + b + 1 = a + b + 2
Even b)is ruled out.
Take c).
f(a+b) = sqrt(a+b) where as f(a) + f(b) = sqrt(a) + sqrt(b)
c) is ruled out.
Take d).
f(a+b) = 2/(a+b) where as f(a) + f(b) = 2/a + 2/b
d) is eliminated.
Take e).
f(a+b) = -3(a+b) = -3a -3b = f(a) + f(b)

So, e) is the correct answer.
Anurag Mairal, Ph.D., MBA
GMAT Expert, Admissions and Career Guidance
Gurome, Inc.
1-800-566-4043 (USA)

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by saketk » Mon Sep 19, 2011 9:08 am
Great! thanks a lot Anurag!
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