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Positive even integers

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Source: — Data Sufficiency |
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by dmateer25 » Sun Jan 25, 2009 4:40 pm
1) x(y+5) is an even integer
if y is odd, x can be even or odd and the result will be even.

INSUFF


2) 6y^2 + 41y + 25 is an even integer

In order for this to be an even integer y must be odd. However, this tells us nothing about x.

INSUFF

Combined:
From statement 2 we know that y is odd. From statement 1 we know if y is odd, x can be even or odd.

INSUFF

I choose E.
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by fighting_cax » Mon Feb 23, 2009 3:20 pm
dmateer25 wrote:
2) 6y^2 + 41y + 25 is an even integer

In order for this to be an even integer y must be odd. However, this tells us nothing about x.
I got lost in this part. How were you able to derive that y must be odd based on the equation given?
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by cramya » Mon Feb 23, 2009 4:31 pm
I got lost in this part. How were you able to derive that y must be odd based on the equation given
Hoping Dmateer will not mind :-)

Rules:

odd+odd = even
even+even=even
even+odd = odd

Same rules above apply to subtraction also

even*even = even
odd*odd=odd
even*odd = even

6y^2+41y+25(ODD) -> even

6y^2 - >always even no matter if y is even or odd

So we now have

6y^2(EVEN) + 41y+ ODD = EVEN

6y^2(EVEN)+25(ODD) = ODD

Therefore the above reduces to
ODD + 41y = even

y has to be odd since only ODD+ODD = EVEN

For 41y to be odd, y has to be odd based on multiplication rules above

Hope this helps!

Regards,
CR
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by welcome » Mon Feb 23, 2009 6:31 pm
IMO E. What is OA?
Shubham.
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by x2suresh » Mon Feb 23, 2009 7:55 pm
agree with E..
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