BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

points are turn joined

Expert replies
by sanju09 » Sat Jun 26, 2010 1:35 am
The side of an equilateral triangle measures 96. The mid points of its side are joined to form another triangle whose mid points are turn joined to form still another triangle. This process is repeated indefinitely. What is the sum of the perimeter of all the triangles so formed along with the original triangle?
(A) 576
(B) 1152
(C) 1176
(D) 1275
(E) 2304
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
Join the discussion
Source: — Problem Solving |

by selango » Sat Jun 26, 2010 2:32 am
First triangle sides are 96

second triangle sides will be 48

third triangle sides will be 24 and so on

Sum perimeters of all triangles =3*96+3*48+3*24+3*12.......

=3*96[1+1/2+1/4+1/8+1/16....]


-->288[1+1/2+1/4+1/8+1/16....]=x

-->[1+1/2+1/4+1/8+1/16....] =x/288

sigma[(1/2)^n]=x/288

sub ans choices in x.It must satisfy left hand side equation.

I cant proceed from this.Any suggestions.
Join the discussion

by albatross86 » Sat Jun 26, 2010 2:36 am
The sides of the first inner triangle will be HALF of the side of the original triangle. The next one will be HALF of the previous one, and so on. Why? Equilateral triangles are symmetric and when you draw such a triangle out you will see this.

So in essence this is an infinite series of the form:

3*(96 + 96/2 + 96/4 + ...)

The sum of an infinite Geometric progression is a/ (1-r) where a is the first term and 2 is the common ratio

=> 3 * 96 / (1 - 0.5)

= 3 * 96 * 2

= 576

Pick A


NOTE: I've attached a picture I drew very amateurishly :D

In that you can see that angle ADE must be equal to AED so, Triangle ADE is equilateral too. Thus x = 48. If you do the same thing for the other two triangles BDF and FEC, you find that triangle DEF is an equilateral triangle with side 96/2 = 48.
Attachments
Equilateral.PNG
Join the discussion

by albatross86 » Sat Jun 26, 2010 2:43 am
If you do not like remembering formulae and prefer artistic/ intuitive / elegant approaches to problems:

First reach the point:

Sum = 3*96* ( 1 + 1/2 + 1/4 + 1/8 + .... )

Consider this sum: 1/2 + 1/4 + 1/8 + ....

If I give you half a pizza, and you're still hungry - you want moaarr! I give you half of the half I have. But you're not satisfied and keep asking for more. I'm going to keep giving you half of what I hold in my hands.

If I do this INFINITELY, the amount of pizza you hold will TEND towards one entire pizza, since I cannot give you more than 1 pizza.

The only way to grasp the abstract concept of infinity is to imagine that at that point, this impossibility of me continually giving you half of what I hold, at infinity, would result in me giving you the entire pizza. Ofcourse in reality this would never happen because infinity cannot be experienced, atleast on this realm :D

So a series of the form (1/2 + 1/4 + 1/8 + ...) is going to tend towards equalling 1, and thus an infinite series will be equal to 1

SO we have 3*96*(1+1) = 576
Join the discussion

by selango » Sat Jun 26, 2010 2:52 am
albatross86,

wow..Nice explanation.

So the sum of an infinite Geometric progression is a/ (1-r) where a is the first term and r is the common ratio

-->288[1/1-0.5]=288*2=576
Join the discussion