my answer is 4.

lets assume O is centre of the circle

length of the (Arc) = 2(Pi) r * (x/360)= 4/3 Pi

8 Pi *x /360 = 4/3 Pi

If we solve this we get x= 60

RU is part of a triangle in a circle with centre O

We know that the triangle has two sides equal OR and OU =4, and central angle =60, therefore the other two angles must be equal and since the sum of all the angles in a triangle =180 , the other two angles = 60.

the triangle is an equilateral triangle and the length of the third side is also 4

My answer 14.

1 to 30 means 30 !

hence here it goes
Now in 30!, we need to find all multiples of 3

3
6=3*2
9=3^2
12=3*4
15=3*5
18=3^2*2
21=7*3
24=8*3
27=3^3
30=3*10
if we count all the 3's we get 14.

THanks for the explanations.