Plz Explain with method

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Nycgrl: Master | Next Rank: 500 Posts; Posts: 124; Joined: Mon May 19, 2008 1:12 pm; Thanked: 3 times

by Nycgrl » Thu Jun 19, 2008 11:24 am

What is the total number of integers between 100 and 200 that are divisible by 3?
(A) 33
(B) 32
(C) 31
(D) 30
(E) 29

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Source: Beat The GMAT — Problem Solving | Thu Jun 19, 2008 11:24 am

kishore: Senior | Next Rank: 100 Posts; Posts: 62; Joined: Fri Dec 21, 2007 2:58 pm; Location: Fremont , California; Thanked: 3 times

by kishore » Thu Jun 19, 2008 11:55 am

You can use the formula:
((max-min)/distance between two consecutive integer)) +1

We can solve above question much more easily by this formula:

max number divisible to 3 = 198
min number divisible to 3 = 102

So total number between 100 and 200 that is divisible to 3 = (198-102)/3 + 1 = 33

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Nycgrl: Master | Next Rank: 500 Posts; Posts: 124; Joined: Mon May 19, 2008 1:12 pm; Thanked: 3 times

by Nycgrl » Thu Jun 19, 2008 11:57 am

Thanks Kishore

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AleksandrM: Legendary Member; Posts: 566; Joined: Fri Jan 04, 2008 11:01 am; Location: Philadelphia; Thanked: 31 times; GMAT Score:640

by AleksandrM » Thu Jun 19, 2008 5:30 pm

Hey kishore, I used the following method.

Since the question is asking for the number BETWEEN, I just subtracted 100 from 200 and divided 100 by 3, which returned a quotient of 33 (I ignored the remainder since we are asked for the number of integers).

Is my correct answer and accident or just another approach to this problem?

https://second-lap.blocked/

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g_beatthegmat: Master | Next Rank: 500 Posts; Posts: 100; Joined: Fri Jul 27, 2007 12:36 pm; Thanked: 6 times

by g_beatthegmat » Thu Jun 19, 2008 10:50 pm

@AleksandrM

Is my correct answer and accident or just another approach to this problem?

This would not always work. Say if the question gave the range of 102 to 200. Difference = 98. Quotient when 98 is divided by 3 = 32. Which isn't the right answer.

The techniques discussed in the posts above are the right ones.

Thanks.

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