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can you please explain outreach.outreach wrote:mean = (a+b+c)/3 - (1)
given eq 3a - b = c =>3a=b+c - (2)
sub 2 in 1
then mean=4a/3
Gurpinder wrote:can you please explain outreach.outreach wrote:mean = (a+b+c)/3 - (1)
given eq 3a - b = c =>3a=b+c - (2)
sub 2 in 1
then mean=4a/3
just how you would approach such a problem.outreach wrote:wht is not clear?
Gurpinder wrote:can you please explain outreach.outreach wrote:mean = (a+b+c)/3 - (1)
given eq 3a - b = c =>3a=b+c - (2)
sub 2 in 1
then mean=4a/3
Gurpinder wrote:just how you would approach such a problem.outreach wrote:wht is not clear?
Gurpinder wrote:can you please explain outreach.outreach wrote:mean = (a+b+c)/3 - (1)
given eq 3a - b = c =>3a=b+c - (2)
sub 2 in 1
then mean=4a/3
i started giving each variable a value....which didnt workout
We need to plug and chug. Plug in a=4, b=2. Now we plug these values into 3a - b = c into order to determine c.Gurpinder wrote:If 3a – b = c, then in terms of a, what is the average (arithmetic mean) of a, b and c?
3a
4a/3
a/3
a/2
a
???? i dont get this one guys....please help me out.
