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by vivek.kapoor83 » Sun Dec 28, 2008 8:46 am
the angle subtended by any arc at centre is double the angle subtended by same arc on circumference.

---Can any1 explain this property of circle to me ....as i am confused.pls explain it by examples.
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by aroon7 » Sun Dec 28, 2008 9:41 am
Image
If O is the center, then:
angle SOQ = 2 angle SPQ

there is a problem in OG related to this below is the link.
https://www.beatthegmat.com/gmatprep-len ... 14631.html

Thanks!
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by aroon7 » Sun Dec 28, 2008 9:43 am
If O is the center, then:
angle SOQ = 2 angle SPQ

there is a problem in OG related to this below is the link.
https://www.beatthegmat.com/gmatprep-len ... 14631.html

Thanks!
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by Ian Stewart » Sun Dec 28, 2008 11:24 am
It's not hard to prove why this should be true. I'll use the diagram from the post above:

-angle QPO is x;
-OP and OQ are both radii, so they're equal. That makes OPQ isosceles, and angle PQO must also be x;
-the angles in OPQ must add to 180, so angle POQ must be 180-2x;
-POS is a straight line, so POQ + QOS must be 180. That makes QOS equal to 2x, or exactly double angle QPO.

If you connect QS, you can continue to fill in angles here to discover that the angle PQS will always be 90 degrees, another useful fact to know.
For online GMAT math tutoring, or to buy my higher-level Quant books and problem sets, contact me at ianstewartgmat at gmail.com

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