BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Please help me with this problem

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Newbie | Next Rank: 10 Posts
Posts: 6
Joined: Fri Feb 10, 2012 12:18 am
by commdiver » Wed Oct 03, 2012 11:35 am
Bradley own b video game cartridges. If Bradley's total is one-third the total owned by Andrew and four times the total owned by Charlie, how many video game cartridges do the three of them own altogether, in terms of b?

A. (16/3)b
B. (17/4)b
C. (13/4)b
D. (19/12)b
E. (7/12)b

[spoiler]I keep getting B, but the answer is C. I assumed Bradley owns 100, which would mean Andrew owns 300 and Charlie owns 25. That gives you a total of 425, which is equal to (17/4)b or (17/4)(100). What am I doing incorrectly?[/spoiler]
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Master | Next Rank: 500 Posts
Posts: 118
Joined: Mon May 21, 2012 10:07 pmFollowed by: 4 members
Thanked: 23 times

by das.ashmita » Wed Oct 03, 2012 11:42 am
Hi commdiver

b = (1/3)a => a = 3b
b = 4c => c = (1/4)b

b+3b+(1/4)b
=(17/4)b

Hence ans should be B

Whats the source??
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Newbie | Next Rank: 10 Posts
Posts: 6
Joined: Fri Feb 10, 2012 12:18 am

by commdiver » Thu Oct 04, 2012 4:58 pm
The problem is from Fractions, Decimals, and Percents (5th edition) by Manhattan GMAT. It is on page 99, as a problem after the fractions, decimals, and percents strategies chapter. Their solution even shows (17/4)b, but they said "C". I am guessing it is just a typo, but I wanted to double check to make sure I also did it correctly.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 3835
Joined: Fri Apr 02, 2010 10:00 pmFollowed by: 523 members
Location: Milpitas, CA
Thanked: 1854 times
GMAT Score:770

by Anurag@Gurome » Thu Oct 04, 2012 9:32 pm
commdiver wrote:Bradley own b video game cartridges. If Bradley's total is one-third the total owned by Andrew and four times the total owned by Charlie, how many video game cartridges do the three of them own altogether, in terms of b?

A. (16/3)b
B. (17/4)b
C. (13/4)b
D. (19/12)b
E. (7/12)b

[spoiler]I keep getting B, but the answer is C. I assumed Bradley owns 100, which would mean Andrew owns 300 and Charlie owns 25. That gives you a total of 425, which is equal to (17/4)b or (17/4)(100). What am I doing incorrectly?[/spoiler]
Number of video game cartridges owned by Bradley = b
Number of video game cartridges owned by Andrew = 3b
Number of video game cartridges owned by Charlie = b/4

Hence, total = (b + 3b + b/4) = [spoiler]17b/4 [/spoiler]

The correct answer is B.
Anurag Mairal, Ph.D., MBA
GMAT Expert, Admissions and Career Guidance
Gurome, Inc.
1-800-566-4043 (USA)

Join Our Facebook Groups
GMAT with Gurome
https://www.facebook.com/groups/272466352793633/
Admissions with Gurome
https://www.facebook.com/groups/461459690536574/
Career Advising with Gurome
https://www.facebook.com/groups/360435787349781/
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Newbie | Next Rank: 10 Posts
Posts: 3
Joined: Tue Jan 01, 2013 11:04 pm
Thanked: 1 times

by Valentin » Sun May 26, 2013 10:41 pm
I had the same problem and I kept getting B as my final answer. So I checked online and I found this:

https://www.manhattangmat.com/errata-fdp-5ed.cfm

As it turns out, the answer is B, it's just that they made a typo.



Hope this helps.

PS: To see other typos in the Manhattan series of books, see the following link:

https://www.manhattangmat.com/errata.cfm

[/b]
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Junior | Next Rank: 30 Posts
Posts: 13
Joined: Sun Jun 12, 2011 7:47 amFollowed by: 1 member

by deepsea13 » Mon May 27, 2013 10:25 pm
I remember doing this problem only a couple of days back.

Here's my explanation:

Bradley Owns 'b' video games.

Andrew owns 3 times as many, so Andrew has '3b' video games.

Bradley owns 4 times as many video games as Charlie. Therefore, Charlie owns 'b/4' video games.

Now the total will be the sum of the number of video games the three own. This works out to an equation which looks like this:

b + 3b + (b/4)

Take 4 as your common denominator, which means mutliplying b x 4 = 4b and 3bx4 = 12b

So now,
(4b + 12b + b)/4 = (17/4)b
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1