1+ 2.2^1 + 3.2^2 + 4.2^3 + ... + 100.2^99 = ?
A) 100.2^100
B) 99.2^100 + 1
C) 99.2^99 + 99
D) 2^100
A) 100.2^100
B) 99.2^100 + 1
C) 99.2^99 + 99
D) 2^100
The Sequence is 1+ 2.2^1 + 3.2^2 + 4.2^3 + ... + 100.2^99[email protected] wrote:1+ 2.2^1 + 3.2^2 + 4.2^3 + ... + 100.2^99 = ?
A) 100.2^100
B) 99.2^100 + 1
C) 99.2^99 + 99
D) 2^100
EVEN+ODD = ODD
So,1+ 2.2^1 + 3.2^2 + 4.2^3 + ... + 100.2^99
In the above sequence highlighted with green one is even.
1+Even should be ODD
Eliminate A and D
Take the last term of the sequence 100.2^99
2^99(99+1) = > 99.2^99 +2^99 > Option C
Eliminate C.
Only option left is B.
So Answer should be B
Regards,
Uva.
