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by knight247 » Tue Aug 23, 2011 10:34 am
If x and y are positive, is y<2?
(1)x>2y
(2)x<y+2

Don't have an OA for this one. Here is my take on it though.

(1)x-2y>0

x=7 and y=1 then x-2y>0 is satisfied and y<2 is satisfied
x=7 and y=3 then x-2y>0 is satisfied but y<2 is not satisfied. Hence Insufficient.

(2)x-y<2

x=7 and y=6 then x-y<2 is satisfied but y<2 is not satisfied
x=2 and y=1 then x-y<2 is satisfied and y<2 is satisfied. Hence Insufficient

Combining both we have...x-2y>0 and x-y<2 multiplying the second statement by -1 we have -x+y>-2 and adding this to the 1st statement we have y<2. Hence C. Hoping to clarify if my logic is correct. Thanks
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Source: — Data Sufficiency |
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by force5 » Tue Aug 23, 2011 11:31 am
Seems right to me. answer should be C
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by HeintzC2 » Tue Aug 23, 2011 12:13 pm
plugging numbers in might have been the long route on this one.

neither 1 nor 2 are sufficient alone.
you can actually plug 2 into 1 yielding:
x>2y & x<y+2 = y+2>2y

subtracting a y from either side we're left with:
2>y.

Answer is C
knight247 wrote:If x and y are positive, is y<2?
(1)x>2y
(2)x<y+2

Don't have an OA for this one. Here is my take on it though.

(1)x-2y>0

x=7 and y=1 then x-2y>0 is satisfied and y<2 is satisfied
x=7 and y=3 then x-2y>0 is satisfied but y<2 is not satisfied. Hence Insufficient.

(2)x-y<2

x=7 and y=6 then x-y<2 is satisfied but y<2 is not satisfied
x=2 and y=1 then x-y<2 is satisfied and y<2 is satisfied. Hence Insufficient

Combining both we have...x-2y>0 and x-y<2 multiplying the second statement by -1 we have -x+y>-2 and adding this to the 1st statement we have y<2. Hence C. Hoping to clarify if my logic is correct. Thanks
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